Receiver JTF tolerance
bhessen at SynthesysResearch.com
Fri Jul 18 11:39:40 PDT 2008
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There appears to be an error going from the equation for frequency
offset on page 9 to the figures on page 10 and forward in your
presentation document 08-248r0. When the offset plotted is only half of
the peak-to-peak offset as the max and min values of Cos(x) are 1 and -1
respectively and the peak-to-peak frequency offset therefore should be
double the values plotted. i.e 14870 ppm at 30 kHz for 6 Gb/s.
These are extremely large values considering that the peak-to-peak
transmitter deviation is 5000 ppm plus/minus frequency tolerance. The
transmitter SSC waveform is often a triangular waveform in which the 30
kHz sinusoidal frequency component is merely 3624 ppm peak-to-peak
followed by a decreasing amount at each odd harmonic of 30 kHz.
I do not see any source of ppm amplification in our SAS channel. We
should certainly make sure that the receivers have some margin (i.e.
that the SSC Waveform becomes a small or insignificant portion of our
jitter budget). 4x margin may however a too much margin. We therefore
suggest that the margin be 2x instead of 4x, this will leave the current
ppm frequency offset numbers as is in the graphs while the UI numbers be
half of the values of your presentation.
SyntheSys Research, Inc.
3475-D Edison Way
Menlo Park, CA 94025
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